Basic help conversion and enthalpy numerical thanku?

There are 2.02 g H2/mol. 12.8 g*1 mol/2.02 g = 6.34 mol H2. If the enthalpy change, ∆H°, is -184.6kJ/mol. Then just multiply 6.34 mol*-184.6 kJ/mol. ∆H = -1 170 kJ